Take the cow across and leave it at point B.
Take the wolf across and leave it at point B, and take the cow back to point A.
Leave the cow at A, and take the hay across to point B.
Then go back and get the cow and take it across.
I win.
Now, my riddle: What do I have in my pocket?
If you like the raft kind of riddle, then you might like this.
http://freeweb.siol.net/danej/riverIQGame.swf
It's kind of fun, but not too difficult.
This is likey a 'chestnut', but a good one if you haven't heard it before.
You are in the basement of an old home. There are three switches on the wall, and one of them turns on a lightbulb up in the attic. How many trips would you need to take before you can state for sure which switch turns on the light (assuming that at least one of them will).
e
Did the woman fall out of the sky?
Was the woman recently swimming?
Is the woman a human? or just a 'female'?
Is the stick used for walking?
Is the stick made out of wood?
Did the stick cause her death?
Did she die from drowning?
Did she die from the results of a fall?
Was she murdered?
Is this too many questions?
How about now?
Was the woman sky diving?
Is the stick part of a rip cord? (maybe a wooden knob on the end, I don't know... I've never been sky diving)
Did the woman jump out of a plane or some other flying object?
Did she fall from a higher object attached to the ground? (i.e. building, cliff, bridge).
Is the fact that she is naked important, or does that just spice up the puzzle?
Was she hanging on the stick for dear life, and when it broke she fell?
Was she paragliding?
... Her dead hand clasps a broken stick...
Was it in fact a plane?
Did she jump out of the plane of her own free will?
Was she pushed or forced out of the plane?
Was the stick part of something that would help keep her from dying?
Was she naked when she left the plane?
Was the flying object gas powered (i.e. helicopter, etc)?
Was the flying object a hot air balloon?
Was the flying object a glider?
Is the broken stick longer than a yard?
Was there anybody else up in the flying object with her?
Did the flying object crash before or after the woman fell?
Was there only one other person in the balloon?
Was this person male or female?
Was the other person trying to harm the woman?
Did she jump from a very high altitude? (say over 50 feet)
Did the woman jump to escape the other person in the balloon?
So, to recap. A woman is up in a balloon, naked, with another person. The woman chooses to jump, and then dies as a result of the fall. She is clutching a broken stick in her hand that is pretty small.
Is any of that incorrect?
Was the male naked?
Is this riddle moving into PG-13 territory?
Did the woman plan on jumping when she first got into the balloon?
Did the man jump?
Is the wooden stick just a wooden stick, or does it serve some other purpose.
Are there markings on the stick?
Is it man made (or carved or altered by man)?
Did the stick used to be attached to the ballon (or balloon carriage)?
Or something in the balloon?
Did she bring the stick with her on the way to the balloon ride?
Did she enter the balloon naked?
Was the stick a match?
Was the woman in danger before she jumped out of the balloon?
I'm assuming that since the woman is naked, she does not have a parachute on?
Is the match unused?
Was she trying to light the burner on the hot air balloon?
Did she take off her clothes to lighten the load of the balloon?
Did the woman think they were still on the ground when she jumped?
Did the woman know she would die when she jumped?
Is the matchstick broken in half?
Would the match light if somebody else struck it?
Is it important that the field in which she lies is 'muddy'?
Are the fields around her also muddy?
Did she break the match?
Did the man break the match?
You mentioned that the woman was in danger before she jumped. Did that danger stemp from the balloon crashing?
Is the male in the balloon related to her? Does she love him?
Was she trying to light something on fire before she jumped?
The man was an alcoholic and knew that he could not resist the addiction, so he asked the bartender to force him away from the only place he could get alcohol.Nope.
Did the gun shoot bullets?Yes, it was a real gun, but the bartender didn't actually shoot the man.
Did the bartender and the man know each other previously?No
Was the bar a speakeasy?no
A murderer is condemned to death. He has to choose between three rooms. The first is full of raging fires, the second is full of assassins with loaded guns, and the third is full of lions that haven't eaten in 3 years. Which room is safest for him?
Um...the room with the lions cause they all died of starvation years ago.
The dictionary.
HOw about this one:
Five hundred begins it, five hundred ends it,
Five in the middle is seen;
First of all figures, the first of all letters,
Take up their stations between.
Join all together, and then you will bring
Before you the name of an eminent king.
The encyclopedia? That would be an interesting encyclopedia. Just what would an entry for "tomorrow" look like.
man, that one and Atlas ball. *grump*:) Hey, if you don't learn anything from a riddle, then it's a sucky riddle.
Police Station
Police Lane
State Police
How fast can you find out what is unusual about this paragraph? It looks so ordinary that you would think that nothing was wrong with it at all and, in fact, nothing is. But it is unusual. Why? If you study it and think about it you may find out, but I am not going to assist you in any way. You must do it without coaching. No doubt, if you work at it for long, it will dawn on you. Who knows? Go to work and try your skill. Par is about half an hour.
My thunder comes before the lightning
My lightning comes before the clouds
My rain dries all the land it touches
What am I?
An exploding microwave. ;D
My thunder comes before the lightning
My lightning comes before the clouds
My rain dries all the land it touches
What am I?
how do you go from a hanging straight to they were fish......you are correct
Did the men know each other?
Were they related?
Were they playing cards?
Did they kill each other?
Were they killed by a person?
Were they killed by the same person?
Is the placement/order of the cards important?
Were the men shot?
Did the men stabbed.
Were the men drowned?
Were the men asphyxiated?
Whoops... :)
Yes, were the men stabbed.
Were the men killed indirectly by the actions of another person? ('m trying to figure out the 'yes/no' answer.
Where they killed by a random act of nature?
Were they *ahem* playing with a full deck?
Is it important to discern the game they were playing?
Were they playing with regular playing cards? Tarrot cards? Uno cards?
Was anybody else playing with them?
Were they playing poker?
Did they die from loss of blood?
Is this room in a building? On a ship? In an airplane? In a hotel? On a train?
Were they in a type of aircraft?
Were they in space?
Did the two men know that death was coming?
So the men were stabbed, but not by another person? Is that correct?
Did the outcome of the game have to do with their death?
Were they playing poker? 21? Solitaire?
Were the men in some kind of craft that floated on water?
Were they in a submarine?
Was this a kind of suicide pact?
did both men die in the same manner?
How many cards are on the table? 52? 53?
Has to be yes or no question/Yes/No
Did one kill the other as an act of mercy, or in anger?
That was 2 yes no questions.
Did one kill the other as an act of mercy (yes/no)
As an act of anger (yes/no)
Did the other man die from:
Drowning?
Suffocation?
Being blown up?
Thirst?
Wait, so it was Asphyxiation?
Did the men have hopes of being rescued?
So, did one person kill the other person in the hopes that one person could last longer?
And the game determined who was to die?
Asphyxiation- a state of asphyxia or suffocation. Condition caused by insufficient intake of oxygen.But the long and short of it is that one of the men ran out of air, right?
So, did one person kill the other person in the hopes that one person could last longer?
And the game determined who was to die?
what cuts deeper than any blade, sears the soul in the fires of hell, and crushes the spirit?
I've got another interim one.
You are staying in a motel one night and your wallet is stolen from your room. You tell the manager who promptly tells you that you must leave, seeing as how you can now no longer pay for your room.
"I will have my family send me the money", you say. But alas, the money will not arive for 7 days.
"If you have something to offer as collateral, then I will allow you to stay" the manager says.
You have a gold chain, but you don't really trust him. You suspect that if you give him the whole chain he will likely take it, then kick you out anyway.
There are 7 links in the chain, and each gold link is worth one night in the motel. You decide that you will give him only one link per night's stay.
How many cuts do you have to make in order to have the proper number of links?
You have to back up your answer with verbiage...
Betrayal
Here's my pseudoriddle:
What makes a good riddle?
(Not puzzle, mind you. Riddle)
the idea is to give him one link at a time, not two at a time.
The original probability was for 1 of 3, or 1 of 10, not 1 of 2, which is a different equation. Whenever something changes (ratio), so does the probability.
What you say is ONLY true of the initial choice.
Yes, but think about it. I know where the Jack of diamonds is. You don't. You pick 1 in 52 cards. That card has a 1 in 52 chance. I, knowing where the card is, remove the other 50 cards and leave one card left. You can't say that the original card has the same chance of being the Jack of Diamonds as the 1 card that is left over...
Here is an article describing how it works.
http://www.straightdope.com/classics/a3_189.html
After you pick your door, the host, as he always does, picks another door and opens it up.
(1) The host knows which door conceals the prize; (2) he only opens doors that do NOT conceal the prize; and (3) he always opens a door.
It's that the host never reveals the correct answer, and (very important), never reveals your own box.
No, but see, it's statistical. Knowing that it's not random (as opposed to you just being lucky/unlucky) is statistically important for determining your odds.Sorry, I misundestood you. I thought you were saying that in defense of not switching.
And no offense, Legion, but she obviously didn't think about my post long enough (did she actually read this thread, or did she just hear your explanation of my post?), or she's not as statistically inclined as you make out. If you're having trouble grasping how it works this way, I recommend you click on Ookla's link and think it out.
This means that your first guess has no impact on whether you will win or lose, it is just like getting a buy round in a tournement. So the only real choice you have in this situation is whether you stay with box 2 or switch to box 1....which is a 50% that yours is right. Now if the host never gave you that chance to switch then you would be right you would only have a 1 out of 3 chance of winning.
I will look at Ookla's link again, but I cannot till tonight.
You can look at it another way. If I gave you three boxes, and said you could either pick one box, or pick two boxes, in hopes to find the 'prize', what would you pick? You would pick two, even though you knew that one of the boxes would be empty. You would rather have two chances at winning than just one.
So, in the scenario, when you 'switch', you are in affect picking the other two boxes, even though you know one of them already is not the prize.
You Pick box 2 in all of the scenarios
scenario 1
1) You pick B
2) C is eliminated
3) A is correct
4) You lose
scenario 2
1) You pick B
2) A is eliminated
3) C is correct
4) You lose
scenario 3
1) You pick B
2) C is eliminated
3) A is incorrect
4) You win
scenario 4
1) You pick B
2) A is eliminated
3) C is incorrect
4) You win
Since half of Y+Z have been eliminated it stands to reason that it loses half of its chances of winning…lowering it down to 1/3 chance of being right.No, because then you are only left with 66 percent total. Just because you know it's wrong, doesn't change the fact that there was a 1 in 3 chance that it was correct.
No, because then you are only left with 66 percent total. Just because you know it's wrong, doesn't change the fact that there was a 1 in 3 chance that it was correct.
Get a buddy, try it with cards, check the percentages...
And Archon, your guess is not correct.
Since it's been more than 24 hours, again... Here is another one.
You and two other very smart people were brought before the President. He want's to see which of you is the smartest, so you can figure out how to lower gas prices.
You are led blind-folded into a small room, and seated around a table. The president describes the test.
"Upon each of your heads I have placed a hat. You are either wearing a blue hat or a white hat. You don't know which, but I will tell you this; at least one of you is wearing a blue hat. There may be only one blue hat and two white hats, there may be two blue hats and one white hat, or there may be three blue hats. But you may be certain that there are not three white hats."
The president explains that when the blindfolds are taken off, the first to correctly announce the color of his hat shall be his advisor.
With that, the president uncovers your eyes and you see that your two competitors are each wearing blue hats. You see from the look in their eyes that they are thinking, "What is the color of my hat?"
For hours nobody speaks, then finally you stand up and say, "The color of the hat I am wearing is..."
What color is your hat? And how do you come to that conclusiong?
Formula is now
A = still your pick
B=another box
C = been eliminated so its zero now
A + (B + 0) = 100% chance of winning...is that right?
So then it's really A + B = 100% chance of winning...2 choices both equal it’s a 50/50 chance that either is true...
Can you show me anything that is wrong with this logic?
According to my analysis, if you keep your box, you should win 10/30 times. According to your analysis, you should win 15/30 times.
This does not chance the fact that the question still leaves you with only 2 choices.
You and two other very smart people were brought before the President. He want's to see which of you is the smartest, so you can figure out how to lower gas prices.
You are led blind-folded into a small room, and seated around a table. The president describes the test.
"Upon each of your heads I have placed a hat. You are either wearing a blue hat or a white hat. You don't know which, but I will tell you this; at least one of you is wearing a blue hat. There may be only one blue hat and two white hats, there may be two blue hats and one white hat, or there may be three blue hats. But you may be certain that there are not three white hats."
The president explains that when the blindfolds are taken off, the first to correctly announce the color of his hat shall be his advisor.
With that, the president uncovers your eyes and you see that your two competitors are each wearing blue hats. You see from the look in their eyes that they are thinking, "What is the color of my hat?"
For hours nobody speaks, then finally you stand up and say, "The color of the hat I am wearing is..."
What color is your hat? And how do you come to that conclusiong?
Let's assume that the truthtellers village does lie to the east. If you asked the person who always lies, they would say, "He would say it does not lie to the East". And if you asked the person who always tells the truth, he would say, "He would say it does not lie to the East."
If I were to pick the liar, and ask him how this person would answer that question (and happened to pick the castout), what would they answer?
Am I on the right vein here?
But assuming that you ask two people, you can be assured that one of them is not the outcast.
If you pointed at the outcast and asked the Truthteller, "If I asked that man if the Truthteller village is to the East, would he answer 'Yes'?" then the only truthful response would be "I don't know."
So, I guess the only thing the Lieteller could do would be the opposite: "I know."
Explain what you would do to get the flagpole into position.
The final equation should have equal values on both sides of the equals sign, so putting one toothpick diagonally across the two that form the equals sign in order to change it into a "not equals" is not allowed.
in other words, neither of the toothpicks in the "equals" sign are the ones that will be moved, and we won't be changing it either. focus on the other 5
H meaning 5 in the swangalian dialect of the hundu atu.